LeeDiddy990 (November 30, 1999 at 12:00 am)

thanks so much for all the explanations it has helped me survive general chemistry and organic chemistry I. chemistry is a hard subject but you have made learning chemistry fun and interesting.

NightVixen0101 (November 30, 1999 at 12:00 am)

Thanks so much chem guy! Your time is really appreciated by all of us! WE LOVE YOU!!!!

bannanaiscool (November 30, 1999 at 12:00 am)

And I don't have a value for the hydrate either! Sorry, mate. And thanks so much for the nice comments. They're very encouraging. I really appreciate it. Chemguy

wingtsunnineoeight (November 30, 1999 at 12:00 am)

hey chem guy! thankyou how sharing your knowledge! i understand the method for calculating the G (free energy change)rather well now! I have only one problem tho :( i have a negative G value which is great, but i wish to approximate this value by checking it against the literiture G value (g = (sum of) G reactants - (sum of) G products) but i cant find the data on any of the thermo tables avalible!!! the reaction is: Zn(s) + Hg2So4(s)+ 7H2O(l) = ZnSO4.7H2O(s) + 2Hg any help would be great!

wingtsunnineoeight (November 30, 1999 at 12:00 am)

I cannot believe that i made it click for me in under half an hour! unbelievable!! For this i am eternally greatful, and i say this from my heart. You have restored my faith in the world of phys chemistry, i can now @ 24 years old finally pick up a physical chemistry book and relate to it :) Thankyou so much Chemguy! you're on the source very kind regards from the UK :) Peter Cook. UNIVERSITY OF KENT

wingtsunnineoeight (November 30, 1999 at 12:00 am)

i have spent years trying to understand thermodynamics and phys chemistry, and i have spoken with many in the hope they might help me understand it, (im not joking! i even went as far as taking tutorials at imperial college London!) and as of today had no luck at all :( then i was drawn to u tube and i found you! you are an incredibly formidable teacher, and many tutors even at the highest level are mere shadows in comparison.

ddrose272 (November 30, 1999 at 12:00 am)

thank you ( im not sure why .. but im posting a comment then we i see the video again either the comment is not there or it is written twice ) any way just wanna tell u thanks u r the best.

sciencehelp (November 30, 1999 at 12:00 am)

Hey, Thanks for your videos. Just wanted to clarify if delta H is positive in that equation does that mean the reation was endergonic? It's the only thing confusing me:( Thanks again, you are like my teacher for this summer

fpitzer (November 30, 1999 at 12:00 am)

Easy to understand and entertaining to watch! Thanks for making chem clear and keeping me awake!

dorothydorothy111 (November 30, 1999 at 12:00 am)

thanks to you i got a seriously spontaneous A for my mark in 12U...whoooo...thanks again...Canada rules lol